January 27, 2023

Easy simplification questions for class 5 with answers and practice questions

Simplification questions for class 5

To  simplify a numerical expression having two or more operations, we use ‘BODMAS’  , where the letters  B, O, D, M,  A,  S stand for Brackets , orders(powers/indices or roots) ,  Division,  Multiplication,  Addition  and  Subtraction  respectively. The following questions  on simplifications has different types of questions that can be practiced by the students to get more ideas to simplify the expressions.

Simplification questions for class 5 (solved examples)

(I) 14 x 7+36÷4+14

sol.  14 x 7+36÷4+14= 14 x 7+9 +14                         (performing division )

= 98+9+14                                  (performing multiplication)

=121

(II) 100-56÷7+15 x 2

Sol. 100-56÷7+15 x 2= 100-8+15 x 2     (simplifying  division)

= 100-8+30           ( simplifying  multiplication) 

= 100+30-8

= 130-8 = 122

(III)  19  [4 + {16  (12  2)}]

Sol.  19 – [4 + {16 – (12 – 2)}] = 19 – [4 + {16 – 10}]                        (Removing  small brackets)

= 19 – [4 + 6]                                    (Removing curly  brackets)

= 19 – 10                                           (Removing square brackets)

= 9

(IV ) 12-[20 ÷{8-2(9-5-2)}]

Sol. 12-[20 ÷{8-2(9-5-2)}]= 12-[20 ÷{8-2 x 2}]                 (removing small brackets)

=12-[20 ÷{8-4}]

=12-[20 ÷4]                                  (removing braces)

= 12-5                                             (removing big brackets)

=7

(V) [24 ÷ {10- (8- \overline{6-2}

)}]

Sol. [24 ÷ {10- (8- \overline{6-2})}] = [24 ÷ {10- (8- 4)}]                  (removing bar)

=[24 ÷ {10- 4}]                           (removing small brackets)

=[24 ÷ 6]                                      (removing braces)

=4                                                    (removing big brackets)

(VI) \mathbf{60 -48 \div 6 \times 4 +8}

Sol. 60 -48 \div 6 \times 4 +8  = 60 -8 \times 4 +8                         (solving division)

= 60- 32 +8                                 (solving multiplication)

= 68 -32                                               ( solving addition)

= 36

(VII)  Simplification questions for class 5 

Sol. 56\div 14 \times 3-10\div 5+1 = 4 \times 3-2+1                 (solving division)

= 12-2+1                                  (solving multiplication)

=13 -2                                       (solving addition)

=11

(VIII) \mathbf{\left [ \left \{ \left ( 30- \overline{9-6} \right )\div 3 \right \}\times 6+6 \right ]}   

Sol. \left [ \left \{ \left ( 30- \overline{9-6} \right )\div 3 \right \}\times 6+6 \right ]=\left [ \left \{ \left ( 30- 3 \right )\div 3 \right \}\times 6+6 \right ]                     (removing bar)

=\left [ \left \{27 \div 3 \right \}\times 6+6 \right ]                                     (removing small brackets)

\left [9\times 6+6 \right ]                                                       (removing curly braces)

= 54 +6                                                                   (solving multiplication)

= 60

(IX)  \mathbf{\left [ 40\div \left \{ 19-3\left ( 6-\overline{4-1} \right ) \right \} \right ]} 

Sol. \left [ 40\div \left \{ 19-3\left ( 6-\overline{4-1} \right ) \right \} \right ]= \left [ 40\div \left \{ 19-3\left ( 6-3 \right ) \right \} \right ]                       (removing bar)

= \left [ 40\div \left \{ 19-3\times 3 \right \} \right ]                                  (removing small brackets)

= \left [ 40\div \left \{ 19-9 \right \} \right ]                                            (solving multiplication  under curly braces}

= \left [ 40\div 10 \right ]                                                           (removing curly braces)

=  4

(X)  \mathbf{100 \times 10 -100 +2000\div 100 }  

Sol. 100 \times 10 -100 +2000\div 100 =100 \times 10 -100 +20                                   (solving division)

=  1000 -100 +20                                                   (solving multiplication)

=  1020 -100                                                             (solving addition)

= 920

Simplification questions for class 5 (Unsolved  problems for practice)

(i) 30÷6+10-2 x 5

(ii)   48÷16 x 2+17 – 9

(iii) (18+10)-(3 x 6)

(iv) (10 x 8) ÷ (20÷5)

(v) {20-(24- 10)}+7

(vi) {20+(15+5)}-5

(vii) 12 x 3 ÷3 x 4-2+6

(viii) 121 ÷ 11+ 29 – 2 x 10

(ix) 45 – [38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3}]

(x)  37 – 6 × 4 + 32 ÷ 8

(xi) 27  [18  {16  (5 \overline{4-1})}]

(xii) 100 x 10 -100+2000÷100

(xiii) 5751 x {45-(90÷2)}

(xiv) 289+153÷17-8 x 19

(xv) 7823-128÷16 of 4 -3973

(xvi) [{64-(12+13)}÷3]+15

(xvii) 4+4+4+4 ÷ 4

(xviii)20- {18÷(7-2+1)}

(xix) 2[19-{7+(12÷4)}]

(xx) [{(30-\overline{9-6})÷3} x 6+6]

Ans.(i)  5    (ii) 14     (iii) 10       (iv) 20      (v) 13      (vi)  35      (vii) 52      (viii) 20    (ix) 26    (x)  17   (xi) 23   (xii) 920 

 (xiii)  0     (xiv)146    (xv)   3848      (xvi) 28  (xvii) 13     (xviii)   17     (xix)   18     (xx) 60

Simplification questions for class 5 PDF

 

Simplification questions for class 5  (Quiz) 

 

294
Created on

Simplification Grade 5

1 / 10

  1. Which of the following operation is performed first in simplifying a numerical expression?

2 / 10

2.  100÷10+10 x 10

3 / 10

3.   49 ÷ 7 x 7+5 x 3 -2

4 / 10

4 .    3 x 8 ÷ 4

5 / 10

4+4+4+4÷ 4

6 / 10

6.   80+800÷ 8

7 / 10

7.  16+8÷ 4-2 x 3

8 / 10

5 x 50+57-57÷ 57

9 / 10

80+[20 x {20-(10÷5)}]

10 / 10

10.   10 x 10 +[400÷ {100-(50-\overline{3 \times 10})}]

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